Time Zone

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)

Total Submission(s): 4337    Accepted Submission(s): 1278

Problem Description

Chiaki often participates in international competitive programming contests. The time zone becomes a big problem.

Given a time in Beijing time (UTC +8), Chiaki would like to know the time in another time zone 

s.

 

 

Input

There are multiple test cases. The first line of input contains an integer 

T (1≤T≤106), indicating the number of test cases. For each test case:

The first line contains two integers a, b (0≤a≤23,0≤b≤59) and a string s in the format of "UTC+X'', "UTC-X'', "UTC+X.Y'', or "UTC-X.Y'' (0≤X,X.Y≤14,0≤Y≤9).

 

 

Output

For each test, output the time in the format of 

hh:mm (24-hour clock).

 

 

Sample Input

3 11 11 UTC+8 11 12 UTC+9 11 23 UTC+0

 

 

Sample Output

11:11 12:12 03:23

 

 

题目大意：

给你UTC+8的时间，求给定时区的时间。

 

模拟题。

是水题没错的，但是不仔细做还是会wa得很惨QAQ...

1、这里的时区并不是标准的时区定义，所以直接根据差值加减就好啦。

2、转化成分钟加加减减或许是最好的方法。

3、X可能是两位数。

我是先把给的时间转移到UTC+0(UTC-0)，这样处理起来感觉更方便。

 

#include
       
        #include
        
         #include
         
          #include
          
           #include
           
            using namespace std;int main(){    int t;    scanf("%d",&t);    while(t--)    {        int a,b;        char s[10];        scanf("%d%d%s",&a,&b,s);        int minute=a*60+b-8*60;        int add=0,pos;        for(pos=4;s[pos]!='\0';pos++)        {            if(s[pos]=='.')break;            add=add*10+s[pos]-'0';        }        if(s[pos]=='.')add=add*60+(s[pos+1]-'0')*6;        else add=add*60;        if(s[3]=='+')            minute+=add;        else            minute-=add;        if(minute>=24*60)            minute=minute-24*60;        if(minute<0)            minute=minute+24*60;        printf("%02d:%02d\n",minute/60,minute%60);    }    return 0;}